<PRE><B>Question 797719</B>
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Use sqrt(whatever) for square root.  For any other index, use sqrt[n](whatever).


So, for your problem write:  sqrt[3](64x^5y^7) and we will interpret that to mean:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt[3]{64x^5y^7}]


Cube root of 64 is 4, cube root of *[tex \Large x^5] is *[tex \Large x\sqrt[3]{x^2}] and cube root of *[tex \Large y^7] is *[tex \Large y^2\sqrt[3]y]


Altogether:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4xy^2\sqrt[3]{x^2y}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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