Question 797266
if a dairy has 475 pounds of milk having a content of 2.5% butterfat
 how many pounds of skimmed milk(with no butterfat)must he remove to have milk with a content of 4% butterfat
:
Let x = amt of skim milk removed
:
.025(475) = .04(475-x)
11.875 = 19 - .04x
.04x = 19 - 11.875
.04x = 7.125
x = 7.125/.04
x = 178.125 lbs of skim milk removed