<PRE><B>Question 797438</B>
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There were *[tex \Large x] girls and therefore *[tex \Large 2x] boys.  Then 24 girls came in, so there were *[tex \Large x\ +\ 24] and this number is 2 times the original number of boys, or *[tex \Large 4x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ =\ x\ +\ 24]


Solve for *[tex \Large x], then calculate *[tex \Large 2x], then calculate *[tex \Large x\ +\ 2x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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