Question 67733
2 + 3i/4 + i
I have tried the following:
(2+3i/4+i)*(4-i/4-i)
(8+10i-3i^2)/16-i^2
11-10i/5
:
You are on the right track here:
This part is right:
{{{((8 + 10i - 3i^2))/((16- i^2))}}}
:
You know that i^2 = -1, replace the i^2 with -1, like you did in the numerator:
{{{((8 + 10i - 3(-1)))/((16- (-1)))}}}
:
{{{((8 + 10i +3 ))/((16 + 1))}}} = {{{((11 + 10i))/((17))}}}
:
I mean you had it!! Just a small math error in the denominator.
 you're not confused