Question 797359
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So what you have is a kite shape.  The easiest point to rotate through 90 degrees counterclockwise is the point that is on one of the axes, namely (0,2).


If you rotate (0,2) 90 degrees to the left, then you end up at (-2,0). 


Next the original point (-2,4) is 2 units up and 2 units left of (0,2), so the rotation of (-2,4) is goint to be 2 units down and 2 units right of (-2,0) (which is the rotation of (0,2).  That is:  (-4,-2).


Next, the original point (-4,2) is on the horizontal line through the original point (0,2) and 4 units to the left.  So the rotation of (-4,2) has to be on a vertical line with (-2,0), the rotation of (0,2), and 4 units down.  That is:  (-2,-4)


Let me know what you get for the position of the last point.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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