Question 797075
6x^3 -5x^2 +5x-3/3x^2 -1
my answer so far is 2x-1 with a remainder of 5x-2.
: 
In the dividsor, You have to put in a position for 0x, 
then follow the rules for long division
:
. . . . . . . . . .________________
3x^2+0x-1|6x^3 - 5x^2 + 5x - 3

:
I ended up with: 2x - 5/3, remainder of 7x - 14/3