Question 797110
given that 
the length of the room is seven times long as its wide
L=7W----------equ:1
where
L be the length
W be the wide
and the perimeter of the room is 64ft.
2[L+W]=64-----equ:2
by substituting equ:1 in equ:2
2[7W+W]=64
   7W+W=64/2
     8W=32
      W=32/8
      W=4
by substituting W=4 in equ:1 we get
L=7*4
L=28
therefore the dimensions of the room are 28ft. and 4ft.