Question 67676
f(x)=x^2-x+9
x=-(A/B) [formula for the x-value of the vertex]
x=-(1/-1)=1
f(x)=(1)^2-(1)+9 [plug-in x=1 and solve for f(x) or y]
f(1)=1-1+9
f(1)=9
So, the vertex is (1, 9)

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Graphing:
{{{ graph( 300, 200, -5, 5, -2, 12, x^2-x+9) }}}