<PRE><B>Question 796876</B>
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Distance equals rate times time.  So if it took *[tex \Large t] hours to drive *[tex \Large d] miles at 60 mph, and it took *[tex \Large t\ -\ 1] hours to drive the same distance at 75 mph] then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  75(t\ -\ 1)\ =\ 60t]


Solve for *[tex \Large t] to get the young man&#39;s (don&#39;t know if he is Geffory or Geffery) driving time.  His parent&#39;s driving time is zero -- the boy went to visit them while they were presumably home the entire time.  Then calculate *[tex \Large 60t] or *[tex \Large 75(t\ -\ 1)] to find the distance.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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