Question 796637
Try to identify the pattern
10 = 2x5 = (2+0x3)(2+3)
40 = 5x8 = (2+3)(2+2x3)
88 = 8x11 = (2+2x3)(2+3x3)


The n-th term of the series is given by
{{{T[n]=1/((2+3(n-1))(2+3n))}}}
{{{T[n]=1/((3n-1)(3n+2))}}}


Now, I think you can proceed yourself.


Cheers!!!