Question 796646
The tags have become diluted to {{{15/65}}}, approximately.


The unknown moose population was p.  When releasing the 72 tagged moose, the tag concentration was to months later become {{{72/p}}}.  Now, the months later, after checking the 65 caught moose, we expect the two ratios to be equal:


{{{72/p=15/65}}}, a proportion.
Their reciprocals are equal,
{{{p/72=65/15}}}
{{{p=72*65/15=72*(13/3)=24*13}}}
{{{p=312}}}, but a good estimate may also be 300 or 310.