Question 796356
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If


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -1\ <\ x\ <\ 0]


Then if *[tex \LARGE x] is near the -1 end of the interval, *[tex \LARGE \frac{1}{x}] is very near to (but smaller than) -1, but as *[tex \LARGE x\ \rightarrow\ 0], *[tex \LARGE \frac{1}{x}] gets very large but in a negative direction. So we can say:  Huge negative number *[tex \LARGE <\ \frac{1}{x}\ <\ -1].  On the other hand, as *[tex \LARGE x\ \rightarrow\ 0], (Huge negative number) cubed *[tex \LARGE < \ \frac{1}{x^3}\ <\ -1]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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