Question 796141

Solve:  x/(x - 4) - 2/(x + 3) = 20/x^2 - x - 12  >>>( "/" indicates fraction bar, not division).

Here is what I have.

x(x+3)/(x-4)(x+3) - 2(x-4)/(x-4)(x+3) = 20/(x-4)(x+3)

I'm stuck here. Is my numerator  of 20 supposed to have the LCD following it also? Ex: 20(x-4)(x+3)/(x-4)(x+3)? Once I get my equation set up to where I can make it equal to zero, I can solve from there.

Thank you for your time!


{{{x/(x - 4) - 2/(x + 3) = 20/(x^2 - x - 12)}}}


{{{x/(x - 4) - 2/(x + 3) = 20/((x - 4)(x + 3))}}}


x(x + 3) - 2(x - 4) = 20 ----- Multiplying by LCD, (x - 4)(x + 3)


{{{x^2 + 3x - 2x + 8 = 20}}}


{{{x^2 + x - 12 = 0}}}


Solve for x, but be reminded that {{{x <> 4}}}, and {{{x <> - 3}}}


You can do the check!! 


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