Question 795822
(a^1 over 3 - b^1 over 3) ( a^2 over 3 + a^1 over 3 b^1 over 3 + b^2 over 3)
If you mean
{{{(a^1/3 - b^1/3)*( a^2/3 + a^1/3)*(b^1/3 + b^2/3)}}}
= {{{(a/3 - b/3)*( a^2 + a)/3*(b/3 + b^2/3)}}}
= {{{(a - b)/3*( a^2 + a)/3*(b^2 + b)/3}}}
= {{{ab*(a - b)*( a + 1)*(b + 1)/27}}}
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With additional info:
{{{(a^(1/3) - b^(1/3))*( a^(2/3) + a^(1/3)b^(1/3) + b^(2/3))}}}
= a - b
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{{{m^3 - n^3 = (m - n)*(m^2 + mn + n^2)}}} a difference of 2 cubes