Question 795723
If the flavors are labeled 1 - 10,
you can have:
flavor 1 with any of 7 toppings
OR
flavor 2 with any of 7 toppings
OR
flavor 3 with any of 7 toppings
etc. . . 
Since you have OR choices,
you add the possibilities
{{{ 7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 = 10*7 }}}
{{{ 10*7 = 70 }}}
There are 70 possible selections of 1 flavor and 1 topping
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You could have done it the opposite way, too
topping 1 with any of 10 flavors
OR
topping 2 with any of 10 flavors
OR
topping 3 with any of 10 flavors
etc. . . 
This gives you {{{ 7*10 = 70 }}}
same answer