Question 795635
 teri begins walking east at 2mph at 1:00.
 Cindy leaves from the same point 30 min. later going east at 3mph.
 when will she catch teri? 
:
since we are using mph, change 30 min to .5 hrs
:
Let t = time for C to catch T
then
(t+.5) = the travel time of T
:
When C catches T, they will have traveled the same distance
Write a distance equation; dist = speed * time
:
3t = 2(t + .5)
3t = 2t + 1
3t - 2t = 1
t = 1 hr for C to catch T
:
:
Check this by finding the actual distance of each, should be equal
3(1) = 3 mi
2(1.5) = 3 mi