Question 795468
Let {{{ x }}} = pounds of 2% clay needed
{{{ .02x }}} = pounds of water in 2% clay
{{{ .01*400 = 4 }}} pounds of water in 1% clay
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{{{ ( .02x + 4 ) / ( x + 400 )= .014 }}}
{{{ .02x + 4 = .014*( x + 400 ) }}}
{{{ .02x + 4 = .014x + 5.6 }}}
{{{ .006x = 1.6 }}}
{{{ x = 1.6/.006 }}}
{{{ x = 266.667 }}}
You end up with {{{ x + 400 }}} pounds of
the 1.4% clay
{{{ x + 400 = 666.667 }}} pounds
check answer:
{{{ ( .02x + 4 ) / ( x + 400 )= .014 }}}
{{{ ( .02*266.667 + 4 ) / ( 266.667 + 400 )= .014 }}}
{{{  5.333 + 4 = .014*666.667 }}}
{{{ 9.333 = 9.333 }}}
OK