Question 795340
Three consecutive integers:
n, n + 1, n + 2.
n + (n + 1) + (n + 2) = 132
n + n + 1 + n + 2 = 132
Collect like terms:
3n + 3 = 132
3n = 132 - 3
3n = 129
n = 43
Three consecutive integers:
43, 44, 45.
Hope this helps.
:-)