<PRE><B>Question 795155</B>
Hector is performing an experiment that requires 160 ml of 40% sulfuric solution. He has a 25% sulfuric acid solution and a 50% sulfuric acid solution. How many ml of each solution should he mix to obtain the needed solution?
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Equation:
acid + acid = acid
0.25x + 0.50(160-x) = 0.40*160
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25x + 50*160 - 50x = 40*160
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-25x = -10*160
x = (2/5)160
x = 64 ml (amt. of 25% solution needed)
160-x = 96 ml (amt. of 50% solution needed)
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Cheers,
Stan H.
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