Question 791592
Evaluate 
Assume the problem is:
{{{log(2,(3)) * log(3,(4)) * log(4,(5)) * log(5,(6)) * log(6,(7)) * log(7,(8))}}} = ?
Not sure if there is an easier way to do this, but it can be done using the
change of base formula: {{{log(a,(N))}}} = {{{log(b,(N))/log(b(a))}}} 
:
A lot of math, so wrote a 10 line basic program that spit it out in milliseconds.
the quotient of these 6 expressions was exactly 3
Interesting that integer values occur:
 the quotient of the 1st two = 2
 the quotient of the given 6 = 3
 the quotient of expressions up {{{log(15,(16))}}} = 4
 the quotient of expressions up {{{log(31,(32))}}} = 5
 the quotient of expressions up {{{log(63,(64))}}} = 6
 the quotient of expressions up {{{log(127,(128))}}} = 7
:
Not sure how relevant this is to anything, but thought it was interesting. CK
Comments? email me at: ankor@att.net