<PRE><B>Question 67530</B>

Let x=her speed going in
Then x+5= her speed returning

distance (d)= rate (r)  times  time (t) or d=rt

distance going=distance returning

distance going=5x
distance returning=4(x+5)

So 5x=4(x+5)

5x=4x+20  subtract 4x from both sides

5x-4x=20
x=20mph----------------------------speed going in
x+5=20+5=25mph----------------------speed returning

Ck

4 hours at 25 mph=5 hours at 20 mph
100=100

and
25=20+5
25=25



Hope this helps----ptaylor</PRE>