Question 794687
{{{x}}}= the measure of the angle, in degrees (you did not specify your angle measure units)
{{{5x}}}= 5 times the angle, in degrees
{{{90^o-x}}}= the measure of the complement, in degrees
(complement means what you need to add to get to {{{90^o}}})
{{{180^o-x}}}= the measure of the supplement, in degrees
(supplement means what you need to add to get to {{{180^o}}})
{{{5x=90^o-x+(180^0-x)-4^o}}} --> {{{5x=90^o+180^0-4^o-x-x}}} --> {{{5x=266^o-2x}}} --> {{{7x=266^o}}} --> {{{x=266^o/7}}} --> {{{highlight(x=38^o)}}}