Question 794339
tanx.cosx - tanx + cosx -1 = 0
{{{(sin(x)/cos(x))*cos(x)-tan(x)+cos(x)-1=0}}}
{{{sin(x)-sin(x)/cos(x)+cos(x)-1=0}}}
{{{cos(x)sin(x)-sin(x)+cos^2(x)-cos(x)=0}}}
{{{sin(x)(cos(x)-1)+cos(x)(cos(x)-1)=0}}}
{{{(cos(x)-1)(sin(x)+cos(x))=0}}}
cos(x)-1=0
cos(x)=1
x=0
..
sin(x)+cos(x)=0
sin(x)=-cos(x)
x=3&#960;/4 (In quadrant II where sin>0 and cos<0)