Question 793758
{{{a^2-2ab+b^2=(a-b)^2}}}
If {{{a^2-2ab+b^2=(a-b)^2}}} is the area of one face of a cube,
the edge of the cube is {{{abs(a-b)}}} ({{{a-b}}} if {{{a>b}}}).
Then the volume of the cube is
{{{(abs(a-b))^3=abs((a-b)^3)=abs(a^3-3a^2b+3ab^2-b^3)}}}
If {{{a>b}}}, I would not need the absolute values.