Question 794071
When you have the sum of two expressions, {{{a}}} and {{{b}}},
and want to calculate the square of that sum you can use the formula for "square of a binomial":
{{{(a+b)^2=a^2+2*a*b+b^2}}}
Applying that to the problem we get
{{{(3sqrt(x)+2)^2=(3sqrt(x))^2+2*(3sqrt(x))*(2)+(2)^2}}}
We keep calculating indicated operations and simplifying.
={{{(3sqrt(x))^2+12sqrt(x)+4}}}
={{{3^2*(sqrt(x))^2+12sqrt(x)+4}}}
={{{9x+12sqrt(x)+4}}}