Question 793748
You should try this on your own using variables.

Assumed given area:  {{{pi*r^2}}}


Scaled down area, using linear {{{(1/2)}}}:  {{{pi*(r/2)^2}}}


How does the second area compare to the given original area?
Given Original, {{{pi*r^2}}}.
Scaled Down by Half, {{{pi*r^2*(1/4)}}}

The scaled-down-by-half area is one quarter of the original.