Question 792749
ln e^(log(x+1)+log(x-2)) = (1/2)e^(ln(2)), what is x?
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log of base raised to a power=power
ln e^(log(x+1)+log(x-2))=log(x+1)+log(x-2)=log(x+1)(x-2)
..
Base raised to the log of number=number
(1/2)e^(ln(2))=(1/2)*2=1
..
log(x+1)(x-2)=1
10^1=(x+1)(x-2)
10=x^2-x-2
x^2-x-12=0
(x-4)(x+3)=0
x=4
or
x=-3