Question 67446
Let h1 be the height of the first reach.
{{{sin(30) = h1/12}}} Solve for h1.
{{{h1 = 12sin(30)}}}
{{{h1 = 12(0.5)}}}
{{{h1 = 6}}}ft.

Let h2 be the new height.
{{{sin(60) = h2/12}}} Solve for h2.
{{{h2 = 12sin(60)}}}
{{{h2 = 12(0.866)}}}
{{{h2 = 10.39}}}
The additional reach = h2-h2
{{{h2-h1 = 10.39-6}}}
Additional reach = 4.4 ft. (To the nearest tenth)