Question 792251
Let's assign the variable differently.
x = son's age now.
f = father's age now.


Two years ago, {{{f-2=4(x-2)}}}.
Simplify this: {{{f-2=4x-8}}}
{{{f-4x=2-8}}}
{{{f-4x=-6}}}
{{{4x-f=6}}}


Three years from now, {{{f+3=3(x+3)}}}.
Simplify this:  {{{f+3=3x+9}}}
{{{f-3x=9-3}}}
{{{f-3x=6}}}
{{{3x-f=-6}}}


If we subtract the second equation from the first equation, we have
{{{(4x-f)-(3x-f)=6-(-6)}}}
{{{x=12}}}


The son's age NOW is 12.
The father's age NOW is{{{ f-2=4(x-2)}}},
{{{f=2+4(x-2)}}}
{{{f=2+4(12-2)}}}
{{{highlight(f=42)}}}
But if you want an expression for f, then return to either original earlier equation and solve for f in terms of x:
{{{f=2+4x-8}}}
{{{highlight(f=-6+4x)}}}