Question 791796
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The perimeter is given by *[tex \LARGE P\ =\ 2l\ +\ 2w].  But we also know that *[tex \LARGE l\ =\ w\ +\ 6], so write:


*[tex \LARGE 2(w\ +\ 6) +\ 2w\ =\ 44]


Solve for *[tex \LARGE w], then calculate *[tex \LARGE w^2\ +\ 6w]. 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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