Question 790924
Solve the equation. (Enter your answers as a comma-separated list. Use n as an integer constant. Enter your response in radians.)
assume:[0,2π]
tan^2 9x = 3
tan(9x)=±√3
..
9x=√3
9x=π/3,4π/3 (In quadrants I and III where tan>0)
x=π/27,4π/27
or
9x=-√3
9x=2&#960;/3,5&#960;/3 (In quadrants II and IV where tan<0)
x=2&#960;/27,5&#960;/27