Question 791418
Sec^2 x - 1 divided by sin^2 x. Solve to where it's equal to sec^2 x
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{{{(sec^2(x)-1)/(sin^2(x))=tan^2(x)/sin^2(x)=((sin^2(x)/cos^2(x))/(sin^2(x)))
=1/cos^2(x)=sec^2(x)}}}