Question 791485
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Is that *[tex \LARGE \frac{11}{2}] or *[tex \LARGE 1\frac{1}{2}]?


No matter.


Let *[tex \Large y] represent the LHS of your inequality.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ \geq\ 3x\ -\ 2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ +\ 2\ \geq\ 3x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{y\ +\ 2}{3}\ \geq\ x]


which is to say


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ \leq\ \frac{y\ +\ 2}{3}]


Plug in whatever the value of *[tex \Large y] actually is and then do the arithmetic. 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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