Question 791355
I'll do the first one to get you started


{{{a^2-b^2+25+10a}}}


{{{a^2+10a-b^2+25}}}


{{{a^2+10a+25-b^2}}}


{{{(a^2+10a+25)-b^2}}}


{{{(a+5)^2-b^2}}} Note: using the perfect square factoring rule


{{{(a+5-b)(a+5+b)}}} Note: using the difference of squares factoring rule


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So {{{a^2-b^2+25+10a}}} factors to {{{(a+5-b)(a+5+b)}}}


In other words, {{{a^2-b^2+25+10a=(a+5-b)(a+5+b)}}}