<PRE><B>Question 791282</B>
&lt;font face=&quot;Times New Roman&quot; size=&quot;+2&quot;&gt;


The time it takes for the first leg of the trip is *[tex \Large\ t_1\ =\ \frac{d}{40}], where time is in hours and distance is in km.  The time for the return trip is then *[tex \Large\ t_2\ =\ \frac{d}{60}]


The total time for the trip is the sum of the two quantities above:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ t\ =\ \frac{d}{40}\ +\ \frac{d}{60}]


Once you have a simplified expression for *[tex \Large t], you can use that to divide into the total distance, *[tex \Large 2d], to find the average rate for the entire trip.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
&lt;div style=&quot;text-align:center&quot;&gt;&lt;a href=&quot;http://outcampaign.org/&quot; target=&quot;_blank&quot;&gt;&lt;img src=&quot;http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png&quot; border=&quot;0&quot; alt=&quot;The Out Campaign: Scarlet Letter of Atheism&quot; width=&quot;143&quot; height=&quot;122&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;/font&gt;
</PRE>