<PRE><B>Question 67387</B>
A.)How many odd three-digit counting numbers less than 300 can be found given that the second digit cannont be 2 or 8? Repitition is permitted.
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# of ways to choose the 1st (hundreds) digit = 2
# of ways to choose the 2nd (tens) digit = 8
# of ways to choose the 3rd (ones) digit = 5
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# of counting numbers that meet the criteris = 2*8*5=80
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B.)How many even three-digit counting numbers can be formed if the second digit is not 0 and the third is not 6? Repitition is permitted.
# of ways to choose the 1st digit = 9
# of ways to choose the 2nd digit = 9
# of ways to choose the 3rd digit = 4
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# of counting numbers that meet the criteria = 9*9*4=324
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Cheers,
Stan H.
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