<PRE><B>Question 791142</B>
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Just eliminate the common factor of t from numerator and denominator, then graph *[tex \Large f(t)\ =\ 2].  Just remember that the original function excludes t = 0 from the domain, so your graph has a hole at (0,2).


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
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My calculator said it, I believe it, that settles it
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