<PRE><B>Question 790966</B>
A boat can travel 24 mi in 3 h when traveling with a current. against the same current, it can travel only 16 mi in 4 h. find the rate of the current and the rate of the boat in still water.
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let x=rate of boat in still water
let c=rate of current
x+c=rate of boat when traveling with the current
x-c=rate of boat when traveling against the current
..
traveling 24 mi in 3hr=8 mi/hr
traveling 16 mi in 4hr=4 mi/hr
..
2 equations:
8=x+c (with current)
4=x-c (against current)
add
12=2x
x=6
c=2
..
rate of boat in still water=6 mi/hr
rate of current=2 mi/hr</PRE>