<PRE><B>Question 790745</B>
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Since there is no *[tex \Large x] in the functtion, the derivative with respect to *[tex \Large x] is zero, and Newton-Raphson fails because of the zero denominator (also because a constant function has no zero).


Now I suspect you really want to differentiate with respect to something that is actually in the function.  Figure out what you really want to do, express it properly, and then repost.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
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My calculator said it, I believe it, that settles it
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