Question 790701
Solve: 12x^3 + 12x^2 - 9x = 0

I forgot how to factor when the first term has an exponent of 3...

Here is what I have so far which isn't much.

3x(3x^2 + 3)(4x - 3)......what do I do from here if this is even right.
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12x^3 + 12x^2 - 9x = 0
Factor out 3x
3x*(4x^2 + 4x - 9) = 0
--> x = 0  ******** Solution #1
The trinomial can't be factored.
4x^2 + 4x - 9 = 0
*[invoke solve_quadratic_equation 4,4,-9]
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Can I factor (3x^2 + 3) more? I know I'm supposed to have at least 3 answers for this problem.