<PRE><B>Question 790683</B>
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There is a factor of 5 and three factors of x in the numerator.  There is a factor of 3, a factor of 5, one factor of x, and 3 factors of y in the denominator.  The numerator and denominator have a factor of 5 and one factor of x in common.  Eliminate the common factors:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \frac{5x^3}{15xy^3}\ =\ \frac{x^2}{3y^3}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
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My calculator said it, I believe it, that settles it
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