Question 67383
A.) Log(base 3)4 + log(base 3)5 = log(base 3)(4x+5)
Log(base 3)20 = log(base 3)(4x+5)
Log(base 3)20 - log(base 3)(4x+5) = 0
Log(base 3)20/(4x+5) = 0
3^0 = 20/(4x+5)
1 = 20/(4x+5)
4x+5 = 20
4x = 15
x = 15/4<br>

B.)log(base 7)6 -log(base 7)(x-1) = log(base 7)3
log(base 7)6/(x-1) = log(base 7)3
log(base 7)6/(x-1) - log(base 7)3 = 0
log(base 7)6/3(x-1) = 0
7^0 = 6/3(x-1)
1 = 6/3(x-1)
3x-3 = 6
3x = 0
x = 3<br>

C.)3log(base x)4 = 2
log(base x)64 = 2
x^2 = 64
x = +/- 8