Question 790526
Two cars leave a city and head in the same direction. After 6 hours, the faster car is 66 miles ahead of the slower car. The slower car has traveled 294 miles. Find the speeds of the two cars.
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Faster Car DATA:
time = 6 hrs ; rate = x mph ; distance = 6x miles
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Equation:
distance = 294+66 = 360 miles
6x = 360
rate = x = 60 mph (Faster car rate)
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Slower car rate = distance/time = 294/6 = 46 mph 
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Cheers,
Stan H.
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