Question 790351
<h4>x-intercept</h4>

To find the x-intercept, plug in {{{y=0}}} and solve for x



{{{2x-y=18}}} Start with the given equation.



{{{2x-0=18}}} Plug in {{{y=0}}}.



{{{2x=18}}} Simplify.



{{{x=(18)/(2)}}} Divide both sides by {{{2}}} to isolate {{{x}}}.



{{{x=9}}} Reduce.



So the x-intercept is *[Tex \LARGE \left(9,0\right)].



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<h4>y-intercept</h4>

To find the y-intercept, plug in {{{x=0}}} and solve for y



{{{2x-y=18}}} Start with the given equation.



{{{2(0)-y=18}}} Plug in {{{x=0}}}.



{{{0-y=18}}} Multiply {{{2}}} and 0 to get 0.



{{{-y=18}}} Simplify.



{{{y=(18)/(-1)}}} Divide both sides by {{{-1}}} to isolate {{{y}}}.



{{{y=-18}}} Reduce.



So the y-intercept is *[Tex \LARGE \left(0,-18\right)].



Now let's plot the points *[Tex \LARGE \left(9,0\right)] and *[Tex \LARGE \left(0,-18\right)] which are the x and y intercepts respectively.



{{{drawing(500, 500, -5,20,-20,20,
grid(0),
graph(500, 500, -5,20,-20,20,0)
circle(9,0,0.03),circle(9,0,0.05),circle(9,0,0.08),circle(9,0,0.10),circle(9,0,0.12),circle(9,0,0.2),circle(9,0,0.25),circle(9,0,0.30),
circle(0,-18,0.03),circle(0,-18,0.05),circle(0,-18,0.08),circle(0,-18,0.10),circle(0,-18,0.12),circle(0,-18,0.2),circle(0,-18,0.25),circle(0,-18,0.30)
)}}}



Now draw a straight line through the plotted points to graph {{{2x-y=18}}}.



{{{ drawing(500, 500, -5,20,-20,20,
grid(0),
graph(500, 500, -5,20,-20,20,0,(18-2x)/(-1)),
circle(9,0,0.03),circle(9,0,0.05),circle(9,0,0.08),circle(9,0,0.10),circle(9,0,0.12),circle(9,0,0.2),circle(9,0,0.25),circle(9,0,0.30),
circle(0,-18,0.03),circle(0,-18,0.05),circle(0,-18,0.08),circle(0,-18,0.10),circle(0,-18,0.12),circle(0,-18,0.2),circle(0,-18,0.25),circle(0,-18,0.30)
)}}} Graph of {{{2x-y=18}}}