Question 789225
There are 9! = 9*8*7*6*5*4*3*2*1 = 362,880 different ways to arrange all 9 letters.


If we think of V and C as one letter, call it z, then we have the "word" "zeraious" and there are 8! = 8*7*6*5*4*3*2*1 = 40,320 ways to arrange these letters. Double this amount to account for CV to get 2*40,320 = 80,640


So there are 80,640 words where V and C are together (either as VC or CV)


So there are 362,880 - 80,640 = <font color="red">282,240</font> different words where V and C are never adjacent to each other.