Question 789098
Solve the second equation for y


2x+y=-4


y = -4-2x


Then use this back in the first equation


4x+2y=-8


4x+2(-4 - 2x)=-8 ... replace y with -4-2x (we've just shown that y = -4-2x)


4x-8-4x=-8


0x-8 = -8


0-8 = -8


-8 = -8


Since this last equation is ALWAYS true (regardless of what x is), this means that there are an <font color="red">infinite number of solutions</font>


So this system is consistent and dependent.