Question 788861
Let {{{ x }}} = grams of 6% solution needed
{{{ .06x }}} = grams of dissolved chemical in 1% solution
{{{ .01*70 = .7 }}} = grams of dissolved chemical in 1% solution
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{{{ ( .06x + .7 ) / ( x + 70 ) = .03 }}}
{{{ .06x + .7 = .03*( x + 70 ) }}}
{{{ .06x + .7 = .03x + 2.1 }}}
{{{ .03x = 2.1 - .7 }}}
{{{ .03x = 1.4 }}}
{{{ x = 46.667 }}}
46.667 g of 6% solution must be used
check:
{{{ ( .06x + .7 ) / ( x + 70 ) = .03 }}}
{{{ ( .06*46.667 + .7 ) / ( 46.667 + 70 ) = .03 }}}
{{{ ( 2.8 + .7 ) / 116.667 = .03 }}}
{{{ 3.5 / 116.667 = .03 }}}
{{{ 3.5 = .03*116.667 }}}
{{{ 3.5 = 3.5 }}}
OK