<PRE><B>Question 788833</B>
 The hypotenuse of a right triangle is 32 cm more than one of the legs. 
If the other leg is 120 cm, how long is the hypotenuse?
:
Let c = the length of the hypotenuse
then
(c-32) = one leg
:
Using a^2 + b^2 = c^2, we have:
120^2 + (c-32)^2 = c^2
FOIL (c-32)(c-32), do the math
14400 + c^2 - 64c + 1024 = c^2
Subtract c^2 from both sides
15424 - 64c = 0
15424 = 64c
c = 15424/64
c = 241 cm is the hypotenuse
:
:
Check this on your calc
other leg 241-32 = 209
Enter {{{sqrt(120^2+209^2)}}} results: 241, confirms our solution</PRE>