Question 788773
PERPENDICULAR TO A LINE								
5      	x	+	1	y  	=	8				
Find the slope of this line										                                                                                                            
										
1	y  	=	-5      	x	+	8    				
Divide by	1									
	y  	=	-5      	x	+	8    				
Compare this equation with y=mx+b,					m= slope & b= y intercept					
slope m =	-5    									
										
The slope of a line perpendicular to the above line will be the negative reciprocal										 1/5
Because m1*m2 =-1										
The slope of the required line will be			 1/5							
										
m=	 1/5	,point	(	3	,	3	)			
Find b by plugging the values of m & the point in										
y=mx+b										
3	=	  3/ 5	+	b						
b=	12/5									
m=	 1/5									
The required equation is		y  	=	  1/ 5	x	+	12/ 5			
										
PARALLEL										
										
										
5    	x	 	1	y  	=	8				
Find the slope of this line										
make y the subject										
1	y  	=	-5    	x	+	8				
Divide by	1									
	y  	=	-5    	x	+	8    				
Compare this equation with y=mx+b										
slope m =	-5    									
The slope of a line parallel to the above line will be the same										
The slope of the required line will be			-5    							
m=	-5    	,point	(	3      	,	3	)			
Find b by plugging the values of m & the point in										
y=mx+b										
3	=	-15      	+	b						
b=	18								- 1/4	
m=	-5    								1 3/4	
Plug value of  the slope  and b					in y = mx +b					
The required equation is		y  	=	-5    	x	+	18      			
										
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