Question 788642
Standard form would be helpful, {{{y=a(x-h)^2+k}}}.  The vertex is the point, (h,k).  You have in this format, {{{y=a(x-2)^2-12}}} and using the other given point, the origin, form the equation {{{0=a(0-2)^2-12}}} allowing to find the value for "a".


{{{0=4*a-12}}}
{{{4a=12}}}
{{{a=3}}}


Finish the values in the standard form equation:
{{{highlight(y=3(x-2)^2-12)}}}